If K1 and K2 are respective equilibrium constants for the two reactions XeF6(g) + H2O (g) XeOF4(g) + 2HF (g) XeO4(g) + XeF6 (g) XeOF4(g) + XeO3F2(g) the equilibrium constant for the reaction XeO4(g) + 2HF (g) XeO3F2(g) + H2O (g) will be (a) K / K

The expression of equilibrium constant for the first reaction will be 2 4 1 6 2 [XeOF ][HF] K = [XeF ][H O] The expression of equilibrium constant for the second reaction will be 4 3 2 2 4 6 [XeOF ][XeO F ] K = [XeO ][XeF ] The equilibrium constant for the final reaction will be 3 2 2 2 4 [XeO F ][H O] K= [XeO ][HF] Hence, 2 1 K K= K Hence, the correct answer is option (d).