3 2 5 3 2 5 2 CH COOH C H OH k = ... i CH COOC H H O According to rate law rate of forward reaction f f 3 2 5 2 R =K CH COOC H H O And rate of backward reaction b b 3 2 5 R =K CH COOH C H OH f b n Eq R = R 3 2 5 f b 3 2 5 2 CH COOH C H OH K = = K K CH COOC H H O 2 -3 1.1×10 K= 7.33 1.5×10 equilibrium constant will remain unaltered.
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