The hybridization of atomic orbitals of the central atom “Xe” in XeO4, XeO2F2, and XeOF4 respectively.

The hybridization is given by the following formula- 1 [ ] 2 H V M C A , where, H=number of orbitals involved in hybridization V=Valence electrons of central atom M=number of monovalent atoms linked with central atom C=Charge on the cation A=Charge on the anion NO2+:H= 1 2 [5+0-1+0]=2 Or sp NO3-:H= 1 2 [5+0-1+1]=3 Or sp2 NH4+:H= 1 2 [5+4-1+0]=4 Or sp3 Thus, the correct option is (a) 2 3 , , sp sp sp