The given reaction is: H 3 3 3 3 2 CH COOH CH OH CH COOCH H O -> This reaction is called Esterification reaction. 121. Hydrolysis of an ester gives acid A and alcohol B. A reduces Fehling solution and oxidation of B gives A. The ester is (a) Methyl formate (b) Ethyl formate (c) Methyl acetate (d) Ethyl acetate Acid (A) reduces Fehling’s solution so it should be formic acid and ‘B’ on oxidation gives ‘A’. Thus ‘B’ should be methanol. ∴The ester is (Methyl formate) 122. The refluxing of (CH3)2NCOCH3 with acid gives (a) (CH3)2NH + CH3COOH (b) (CH3)2NCOOH + CH4 (c) 2CH3OH + CH3CONH2 (d) 2C
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