Assertion: Consider the following synthesis CH3ONa + PhBr Path–II yields better yield of product than Path-I. Reason: CH3ONa is stronger base than PhONa.

Both the reactions that are given in the assertion are substitution reactions in which nucleophiles change. Bromine is a better leaving group and Hence, the reaction gives a better yield. Path II yields better yield of the product than path I. 3 CH ONa is a stronger base than PhONa , the basicity increase with the increase in the electron density of the molecule and possess a greater negative charge due to the positive inductive effect. O Br + ONa ONa + CH CH Br 3 2 ONa + CH CH OH 3 2 Path I Path II 3 3 CH OPh CH Br PhONa -> SOLID STATE 41 Hence, the correct answer is an option (