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MEDIUMMCQ SINGLEIChO (Chemistry Olympiad)Inorganic ChemistryAlkyl and Aryl HalidesE elimination follows an antiperiplanar structure

Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms. A is (NEET 2018) (a) CH CH (b) CH CH

C.CH
Explanation

The given reaction takes place as follows: 2 / Na/dryether 4 3 3 3 Step 1 Wurtzreaction Step 2 -> -> Br hv A CH CH Br CH CH Step 1: Alkyl halide is formed by free radical halogenation of alkane in the presence of UV-light. Step 2: The formed alkyl halide reacts with sodium in the presence of dry ether to form alkane containing double number of carbon atoms present in alkyl halide. This reaction reaction is known as Wurtz reaction. From the above reaction, it is concluded that option (d) is correct as in all other cases the hydrocarbon formed in step 2 will have four carbon atom

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