The given reaction takes place as follows: 2 / Na/dryether 4 3 3 3 Step 1 Wurtzreaction Step 2 -> -> Br hv A CH CH Br CH CH Step 1: Alkyl halide is formed by free radical halogenation of alkane in the presence of UV-light. Step 2: The formed alkyl halide reacts with sodium in the presence of dry ether to form alkane containing double number of carbon atoms present in alkyl halide. This reaction reaction is known as Wurtz reaction. From the above reaction, it is concluded that option (d) is correct as in all other cases the hydrocarbon formed in step 2 will have four carbon atom
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