Assertion: Treatment of either enantiomer of 2-chlorobutane with ethanolic KOH results in trans-2- butene as major elimination product. Reason: Elimination with ethanolic KOH is a bimolecular reaction.

The elimination reaction of either of the enantiomers of 2-chlorobutane with ethanolic KOH is an E2 elimination. The halide and the hydrogen should be anti to each other. The mixture of enantiomers gives trans as the major product. Let's consider an E2 elimination of 2- chlorbutane. The elimination of halide and hydrogen are possible in their enantiomers. The elimination results in two products which are trans-2-butene and cis-2- butene.In the two sawhorse conformations, the first conformation is more stable which in turn results in trans product. Therefore, trans butane is a major product. Th