Tert-butoxide being a very strong base, elimination must take place. 49. When CH3CHClCH2CH3 is treated with alcoholic KOH, the major product is (a) CH3 – CH = CH – CH3 (b) CH2 = CH – CH2 – CH3 (c) CH3 – CHOH – CH2 – CH3 (d) CH3 – CH2 – CH2 – CH3 When 3 2 3 CH CHClCH CH is treated with alcoholic KOH, elimination reaction takes place. Chloride along with hydrogen is eliminated. Now, the elimination of the particular hydrogen is decided by the Saytzeff’s rule. It says that the hydrogen is eliminated from the beta carbon which has less number of hydrogen. Now, let us look at the compound. 1 2
Take chapter-wise tests, track your progress, and master Alkyl and Aryl Halides.
Start Free Practice →