Major product of the following reaction is: (a) (b) (c) (d)

3 2 CH NH is a weak agent. Thus, the elimination is 1 E - Type. The bromine atom will be eliminated and a hydrogen atom from the beta carbon atom. The mechanism is given below: 46. n-Propyl bromide on treatment with ethanolic potassium hydroxide produces (a) Propane (b) Propene (c) Propyne (d) Propanol The treatment of ethanolic potassium hydroxide with n- propyl bromide leads to an elimination reaction. In the elimination reaction, unsaturated compounds are produced by the elimination of a leaving group. Let us see the reaction: 3 2 2 3 2 2 Potassium Bromide Ethanolic Pot