No rearrangement is possible in E2 mechanism. So, only product a is possible for the given reaction. 72. If tert-butyl bromide and NaNH2 reacts, the product formed is (a) tert-butylamine (b) tert-butylammonium bromide (c) a mixture of butyl amines (d) iso butylenes This is an 2 E -mechanism. The bromine atom will be removed from alpha-carbon atom and the hydrogen atom will removed from the beta-carbon atom. Since all the methyl group are alpha-methyl group, all the methyl group will give same product. The reaction given below: 73. Choose the correct major product of the reaction: (a)
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