HARDMCQ SINGLEIChO (Chemistry Olympiad)Physical ChemistryThermodynamics and ThermochemistryAchiever Section
In an isobaric process, when temperature changes from 1T to T , S is equal to
A.2.303 Cp log (T2/T1)✓ Correct
B.2.303 Cp ln (T2/T1)
C.Cp ln (T1/T2)
D.Cv ln (T2/T1)
Explanation
The entropy changes for a process, when T and P are the variables is given by 2 2 p 1 1 T P S C ln R ln T P For an isobaric process 1 2 P p . Hence the above equation reduces to 2 p 1 T C ln S T or 2 p 1 T S 2.303C log T
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