MEDIUMMCQ SINGLEIChO (Chemistry Olympiad)Physical ChemistryThermodynamics and ThermochemistryPrevious Year Questions
For vaporization of water at 1 atmospheric pressure, the values of ∆H and ∆S are 40.63 kJ mol–1 and 108.8 J K–1 mol–1, respectively. The temperature when Gibbs’ energy change (∆G) for this transformation will be zero, is (Mains 2010)
A.273.4 K
B.393.4 K
C.373.4 K✓ Correct
D.293.4 K
Explanation
According to Gibbs equation, ∆G = ∆H – T∆S when ∆G = 0, ∆H = T∆S Given, ∆H = 40.63 kJ mol–1 = 40.63 × 103 J mol–1 ∆S = 108.8 J K–1 mol–1 3 H 40.63 10 T 373.4K S 108.8 x
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