MEDIUMMCQ SINGLEIChO (Chemistry Olympiad)Physical ChemistryThermodynamics and ThermochemistryState/Phase Change of Reactants and Products
The densities of graphite and diamond at 298 K are 2.25 and 3.31 g cm–3, respectively. If the standard free energy difference is equal to 1895 J mol–1, the pressure at which graphite will be transformed into diamond at 298 K is
A.11.08 × 108 Pa✓ Correct
B.9.92 × 107 Pa
C.9.92 × 106 Pa
D.11.08 × 106 Pa
Explanation
G P V Work done 3 3 12 12 V 10 L 1.71 10 L 3.31 2.25 x x G = Work done = – (–1.71 × 10–3) × P × 101.3 J 3 –3 1895 P 10.93 10 atm 1.71 10 101.3 x x x = 11.08 × 108 Pa ( 1atm 101325Pa) Relationship Between ΔH and ΔU
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