HARDMCQ SINGLEJEE Mains ChemistryPhysical ChemistryThermodynamics and ThermochemistryAchiever Section

In an isobaric process, when temperature changes from 1T to T , S is equal to

A.2.303 Cp log (T2/T1)✓ Correct

B.2.303 Cp ln (T2/T1)

C.Cp ln (T1/T2)

D.Cv ln (T2/T1)

Explanation

The entropy changes for a process, when T and P are the variables is given by 2 2 p 1 1 T P S C ln R ln T P For an isobaric process 1 2 P p . Hence the above equation reduces to 2 p 1 T C ln S T or 2 p 1 T S 2.303C log T

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