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MEDIUMMCQ SINGLEJEE Advanced ChemistryPhysical ChemistryThermodynamics and ThermochemistryPrevious Year Questions

The densities of graphite and diamond at 298 K are 2.25 and 3.31 g cm–3, respectively. The standard free energy difference ( G ) is equal to 1895 J mol–1, the pressure at which graphite will be transformed into diamond at 298 K is (2004)

A.9.92 × 108 Pa✓ Correct
B.9.92 × 107 Pa
C.9.92 × 106 Pa
D.9.92 × 105 Pa
Explanation

G P V Work done –3 –3 12 12 V 10 L 1.71 10 L 3.31 2.25 x x G = work done = – (–1.71 × 10–3) × P × 101.3J 3 –3 1895 P 10.93 10 atm 1.71 10 101.3 x x x = 11.08 × 108 Pa ~ 9.92 × 108 pa ( 1 atm = 101325 Pa)

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