The weight of pure NaOH required to prepare 250 cm3of 0.1N solutions is

The normality of a solution is written as, weight of solute n-factor 1000 Normality = molecular weight V ml x x Given: The volume of the solution is 3 V= 250 cm Normality of solution is N = 0.1 N SOLUTIONS 32 NaOH has one replaceable hydroxide ion. Hence, the n- factor for NaOH is 1. The molecular weight of NaOH is M W of NaOH 40 g/ mol Let's calculate the weight of NaOH the required. weight of NaOH 1 1000 0.1 = 40 250 40 0.1 250 weight of NaOH 1000 weight of NaOH 1 g xx x x >> >> Therefore, 1 gram of NaOH is required to prepare a solution. Thus, (b) is the correct option.