Vapour pessure of CCl₄ at 25ºC is 143 mm Hg. 0.5g of a non-volatile solute (mol. wt. 65) is dissolved in 100 cm3 of CCl₄. Find the vapour pressure of the solution. (Density of CCl₄ = 1.58 g/cm3).

Given that, 4 4 0 B B CCl -3 CCl P =143mmof Hg V=100 ml W =0.5g M =65g/mol M =154g/mol d =1.58 g cm Now, 4 4 4 4 4 4 4 W 0.5 n 65 Also, 1.58 100 158 W 158 n 154 x x B B B CCl CCl CCl CCl CCl CCl CCl M W d V W d V M 4 0 0 Now, P n P n 0.5 158 = 65 154 0.5 154 = 65 158 = 0.007 x B CCl P 143 0.007 143 143 1.07 143 1.07 141.93 >> >> P P P