HARDMCQ SINGLENEET ChemistryPhysical ChemistrySolutionsAchiever Section

The normality of 10% (weight/volume) acetic acid is

A.1 N

B.10 N

C.1.7 N✓ Correct

D.0.83 N

Explanation

10grams of acetic acid in 100ml of water Thus, 100g acetic acid would be present in 1000ml of water. 60g = 1 mole of acetic acid Therefore, 100g will have = (100/60) = 1.67 mole In case of acetic acid 1N solution is equal to 1M solution.

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