To observe an elevation in boiling point of 0.050C, the amount of a solute (molecular weight = 100) to be added to 100 g of water (Kb =0.5) is (WB JEE 2014)

Elevation of boiling point, b b w K 1000 T M W g x x x (Here, w and W = weights of solute and solvent respectively.) M = molecular weight of solute and Kb = Molar elevation constant. On substituting values, we get w 0.5 1000 0.05 100 100 x x x or 0.05 100 100 w 1g 0.5 1000 x x x SOLUTIONS 62