Chem Mantra
HomeCoursesOnline TestsForum
ForumQuestion Bank0.052 100.052 6 / 60 x x x x b b b b b o b T T …
MEDIUMMCQ SINGLENEET ChemistryPhysical ChemistrySolutionsDepression in freezing point

0.052 100.052 6 / 60 x x x x b b b b b o b T T T T T T C 102. An aqueous solution of Glucose freezes at –0.186 °C. Given that 0.512 H O b K K kg mol and 1.86 H O f K K kg mol , the elevation in boiling point of this solution is

A.0.0585 °C
B.0.0512 °C✓ Correct
C.1.864 °C
D.0.0265 °C
Explanation

f f T K m x b b T K m x 0.186 1.86 xm 0.1 / m mol kg 0.512 0.1 0.0512 x o bT C 103. On freezing an aqueous solution of sugar, the solid that starts separating out is (a) sugar (b) ice (c) solution with the same composition (d) solution with a different composition. Depression in Freezing point states that- f f T K m , where f T =depression in freezing SOLUTIONS 46 point, f K =molal freezing point constant and m=molality. The temperature at which liquid and the solid state exist in equilibrium and have same vapour pressure is called freezing point. When vapor pressure of

Back to Question Bank

Practice More Like This

Take chapter-wise tests, track your progress, and master Solutions.

Start Free Practice →
Sponsored

Master Chemistry for JEE, NEET & IChO

Access 19,000+ solved questions with expert explanations, chapter-wise tests, and full video lectures — all in one platform.

NEET Chemistry
Explore Courses →Sign In Free