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Dissolution of 1.5 g of a non-volatile solute (molecular weight = 60) in 250 g of a solvent reduces its freezing point by 0.01 °C. Find the molal depression constant of the solvent. (MHT CET 2014)

A.0.01
B.0.001
C.0.0001
D.0.1✓ Correct
Explanation

Depression in freezing point, f f T K m x Where, m – molality weight of solute 1000 molecular weight of solute weight of solvent x x 1.5 1000 0.1 60 250 x x f f f f T K 0.1 0.01 K 0.1 0.01 K 0.1 0.1 x >> x

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