An aqueous solution of urea containing 18g urea in 1500 cm3 of the solution has a density equal to 1.052 g/cm3. If the molecular weight of urea is 60, then the molality of the solution is

18 g of urea = 18 60 moles = 0.3 moles 18 g of urea is present in1500ml of solution 18 0.012 1500 g of urea is present per ml of the solution. The solution density is given as 1.052 / g ml . every ml of solution has 0.012 g of urea and 1.052 0.012 1.04 g of solvent. SOLUTIONS 30 Let’s calculate molality of solution. we have, w 1000 molality (m) = MW weight of solvnet in Kg x x Substitute values in the equation. we have, Molality of solution is determined as follows, 0.012 1000 m = 0.192 m 60 1.04 x x