Ag crystallises as fcc. If radius of Ag is 144 pm then its density will be (a)₁₀ g cm–3

Density is given by the formula, 3 a Z M d a N x x Given, Radius=144pm and f.c.c. lattice For f.c.c lattice, 4 2 r a Thus, edge length,a= 4 4 144 407.35 2 2 r pm x Now, 3 10 3 23 4 108 10.6 (407.35 10 ) 6.022 10 x x x x d gcm Thus, the correct option is (a) 3 10gcm