Copper crystallises in fcc lattice with a unit cell edge of 361 pm. The radius of copper atom is

As given that copper crystallizes in FCC lattice (Face centered cubic). In FCC atoms are present at the corners of the cubic unit cell as well as on the face centers of each face. The atoms on the face diagonal will be touching each other. Let, the radius of the atom be r and edge length of the cube be a. Face diagonal of cube Solid state 38 r+2r+r= 2a 2a 361 r= = pm=128pm 4 2 2 >> >> Hence the correct answer is option (c)