MEDIUMMCQ SINGLEJEE Advanced ChemistryInorganic ChemistrySolid statePrevious Year Questions
Structure of a mixed oxide is cubic close packed (ccp). The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B. The formula of oxide is (CBSE AIPMT 2012) (a) ABO (b) A BO (c) A B O (d) AB O
Answer
D
Explanation
From ccp arrangement, number of 2 O ions = 4 (Number of octahedral voids) Thus, number of tetrahedral voids 4 2 8 x Number of 2 A ions 1 8 2 4 x Again B ions occupied all octahedral voids. Number of B ions = 4 A:B:O 2:4:4 1:2:2 Structure of oxide 2 2 AB O
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