Ag forms ccp lattice and X-ray studies show that the edge length of its unit cell is 408.6 pm. Find the density of silver. (Given that atomic mass of silver = 107.9 u)

As the lattice is ccp, the number of Ag atoms per unit cell ⇒ Z = 4. Molar mass of Ag = 107.9g mol-1 = 107.9 × 10-3 kg/mol Edge length of unit cell 12 a 408.6pm 408.6 10 m >> x Density 3 A ZM d a N 3 1 3 12 23 1 4 107.9 10 kg mol 408.6 10 m 6.022 10 mol x x x x 3 3 3 10.5 10 kg m 10.5gcm x