For the reaction, H PO NaOH NaH PO H O → What is the equivalent weight of H₃PO₂? (mol. wt. is M)

3 2 2 2 0 1 +1 H PO NaH PO change in oxidation state = 0 M → 30. For the reaction, Fe₀.95 O (molar mass: M) → Fe₂O₃. What is eq. wt. of Fe₀.95O? (a) M 0.85 (b) M 0.95 (c) M 0.8075 (d) None of these 0.95 2 3 Fe O Fe O 2 n-factor (3 ) 0.95 0.85 0.95 Molecular weight Atomic weight Thus, equivalent weight = n-factor M equivalent weight 0.85 → x >>