When copper is treated with a certain concentration of nitric acid, nitric oxide and nitrogen dioxide are liberated in equal volumes according to the equation. o xC u yH NO Cu NO NO NO H O → The coefficients x and y are

3 6 2- 3+ 4 CrO 2Cr Change in oxidation state=6 3 3 V.f Mw = 3 → >> 111. The equivalent weight of MnSO₄ is half its molecular weight when it is converted to (a) Mn₂O₃ (b) MnO₂ (c) 4 MnO (d) 2 4 MnO Ans (b) Sol. 2 - 2- MnSO Mn O MnO MnO MnO 4 3 2 4 4 7 2 4 3 6 Change in oxidation state=4 2 2 V.f >> REDOX REACTIONS 20 112. In the reaction 2 3 2 5 VO Fe O FeO V O → the eq. wt. of V₂O₅ is equal to its (a) mol. Wt. (b) mol. wt./8 (c) mol. wt./6 (d) None of these Ans (c) Sol. 2 5 +2 5 2 5 2VO V O Change in oxidation state=5 2 3 V