Let us consider the oxidation number of S is x. Now by adding all the charges and equating it to overall charge, we get- 2- 3 2- 2 4 2- 2 6 SO x-6=-2 x=+4 S O 2x-8=-2 x=+3 S O 2x-12=-2 x=+5 → >> → >> → >> Therefore, 2- 2- 2- 2 4 3 2 6 S O <SO <S O is the correct order.
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