MEDIUMMCQ SINGLEIChO (Chemistry Olympiad)Physical ChemistryRedox Reactions/Volumetric AnalysisConcept of Oxidation and Reduction
When sulfur dioxide is passed in an acidified K₂Cr₂O₇ solution, the oxidation state of sulfur is changed from
A.+4 to 0
B.+4 to +2
C.+4 to +6✓ Correct
D.+6 to +4
Explanation
The reaction can be written as- 4 6 2- 2- 3+ 2 2 7 4 2 S O +Cr O 3 S O +2Cr +H O → Change in oxidation state is from +4 to +6.
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