Let us consider the oxidation states of iodine for each given compound as x 4 3 5 5 6 HIO 1+x-8=0, x =+7 H IO 3+x-10=0, x = +7 H IO 5+x-12= +7, x = +7 → → → Therefore, option (c) is correct.
Take chapter-wise tests, track your progress, and master Redox Reactions/Volumetric Analysis.
Start Free Practice →