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Forum Question BankOxidation number of nitrogen in (NH₄)₂SO₄ is

MEDIUMMCQ SINGLENEET ChemistryPhysical ChemistryRedox Reactions/Volumetric AnalysisConcept of Oxidation and Reduction

Oxidation number of nitrogen in (NH₄)₂SO₄ is

A.– 1/3

B.– 1

C.+ 1

D.– 3✓ Correct

Explanation

NH ⇒x+4(+1)=+1 ⇒x=-3 Hence, the oxidation state of N is -3.

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