It is a redox reaction that needs to be balanced 2+ 2- + 2+ +3 2 7 2 2 xUO +Cr O +yH aUO +zCr +bH O → We write the reaction in two halves. Oxidation Half: 2+ 2+ 2 UO UO → Reduction Half: 2- 3+ 2 7 Cr O 2Cr → Then, the hydrogen and charge is balanced- 2- + - 3+ 2 7 2 Cr O +14H +6e 2Cr +7H O → 2+ 2+ + - 2 2 UO +H O UO +2H +2e → Thus, the balanced equation is- 2+ 2- + 2+ +3 2 7 2 2 3UO +Cr O +8H 3UO +2Cr +4H O → Thus, the correct option is (a) x y z 3 8 2
Take chapter-wise tests, track your progress, and master Redox Reactions/Volumetric Analysis.
Start Free Practice →