Oxidation state of nitrogen is correctly given for Compound Oxidation State

Let us consider the oxidation number of N is x. Now by adding all the charges and equating it to zero, we get- 3 2 2 2 5 2 4 3 5 3 Mg N 3×2+2x=0 x=-3 NH OH x+2-1=0 x=-1 (N H ) SO 4x+10+6-8=0 x=+2 [Co(NH ) Cl]Cl (NH ) x-3=0 x=+3 → >> → >> → >> → → >> In option D, 3 (NH ) is a neutral ligand. Therefore, on equating this to zero we get oxidation number of nitrogen.