MEDIUMMCQ SINGLEJEE Advanced ChemistryPhysical ChemistryRedox Reactions/Volumetric AnalysisConcept of Oxidation and Reduction

The oxidation number of nitrogen in NaNO₂ is

A.+1✓ Correct

B.+2

C.+3

D.–1

Explanation

Let us consider the oxidation number of P is x. Now by adding all the charges and equating it to zero, we get- Barium has +2 charge on it. Hydrogen has +1 charge on it Oxygen has -2 charge on it. 2 2 2 Ba(H PO ) =2+4+2x-8=0 x=+1

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