The electronic configuration of an element with atomic number 38 is- 2 2 6 2 6 2 10 6 2 1s 2s 2p 3s 3p 4s 3d 4p 5s . The outermost shell of a given element is 2 5s , so it belongs to the 5th period and IIA ( 2 electrons) group. Therefore, the correct option is a.
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