MEDIUMMCQ SINGLEJEE Advanced ChemistryInorganic Chemistryp -Block Elements (group 15-18)Previous Year Questions
Xenon hexafluoride reacts with silica to form a xenon compound X. The oxidation state of xenon in X is (JIPMER 2018)
A.+2
B.+4
C.+6✓ Correct
D.0
Explanation
Xenon hexafluoride reacts with silica to form XeOF₄ as 2XeF₆ + SiO₂ → 2XeOF₄ + SiF₄ The oxidation state of xenon in XeOF₄ is + 6 as calculated below: Let the oxidation state of Xe is a. a + 1 x (–2) + 4 x (–1) = 0 a – 2 – 4 = 0 a = + 6
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