Given, Mass of sodium carbonate M = 106 g/mol Let, Mass of water present molecules present in hydrate state = x Mass of hydrated sodium carbonate = M +x Therefore, 54.3% x 100/M+x 54.3% x 100/106+x x=125.94g/mol No. of water molecules -125.94/18=7 x x The formula of the hydrate is 2 3 2 Na CO .7H O .
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