MEDIUMMCQ SINGLEIChO (Chemistry Olympiad)Physical ChemistryMole _ Equivalent ConceptApplications of Strength of Solutions

A standard solution of 0.165 M HCl is being used to determine  the  concentration  of  an  unknown  NaOH solution. If 25.5 mL of an acid solution are required to  neutralize  15.0  mL  of  the  base,  what  is  the molarity of the NaOH solution ?

A.(0.165)/ (25.5 + 15.0) M
B.(15.0) / (0.165) (25.5) M
C.(0.165) (15.0/25.5) M
D.(0.165) (25.5/15.0) M✓ Correct
Explanation

Given- 45 MOLE & EQUIVALENT CONCEPT 1 1 2 2 1 1 2 2 2 2 ( ) 0.165 ( ) 25.5 ml ( ) 15.0 ( ) ? M ( ) ( ) 0.165 25.5 15 0.165 25.5 15 M HCl M V HCl V NaOH ml M NaOH V HCl M V NaOH M M M >> >> x x x >> Thus, (d) is the correct option.

Practice More Like This

Take chapter-wise tests, track your progress, and master Mole _ Equivalent Concept.

Start Free Practice →