MEDIUMMCQ SINGLEIChO (Chemistry Olympiad)Physical ChemistryMole _ Equivalent ConceptStrength of Solution

The density of 1 M solution of NaCl is 1.0585g mL– 1. The molality of the solution is

A.1.0585

B.1.00✓ Correct

C.0.10

D.0.0585

Explanation

According to question, 41 MOLE & EQUIVALENT CONCEPT m = mole of NaCl/weight of solvent Weight of solvent = weight of solution − weight of NaCl. = 1.0585×1000−58.5 = 1058.5−58.5=1000g=1kg So, m = 1/1 = 1

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