20.0 kg of N₂(g) and 3.0 kg of H₂(g) are mixed to produce NH₃ (g). The amount of NH₃(g) formed is (Kerala CEE 2011)

Given, Weight of nitrogen ( 2 N ) = 20.0 kg Moles of nitrogen = 20000 714.285714286 28 moles Weight of hydrogen ( 2 H ) = 3.0 kg Moles of hydrogen = 3000 1500 2 moles Amount of ammonia formed =? The balanced chemical equation is 2 2 3 3 2 N H NH → As per balanced reaction, 1 mole of nitrogen reacts with 3 moles of hydrogen to form two moles of ammonia. Then, 714.2858 moles of nitrogen requires 2142.8574 moles of hydrogen but it contains only 1500 moles. Hence, hydrogen is the limiting reagent and production of ammonia will be based on the moles of hydrogen. No of moles of hydrogen