MEDIUMMCQ SINGLENEET ChemistryPhysical ChemistryMole _ Equivalent ConceptStrength of Solution
Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is
A.0.44 mol Kg–1
B.1.14 mol kg–1
C.3.28 mol kg–1
D.2.28 mol kg–1✓ Correct
Explanation
Density of given solution= 1.02 g/ml. Clearly, 1.02g/ml means 1020g/ litre. Now, mass of solvent= mass of solution- mass of solute =1020-123g=897g. Molality of the prepared solution is 123 1000 / 60 897 2.28 / mol kg x x
Practice More Like This
Take chapter-wise tests, track your progress, and master Mole _ Equivalent Concept.
Start Free Practice →