MEDIUMMCQ SINGLEJEE Mains ChemistryPhysical ChemistryMole _ Equivalent ConceptEquivalent Weight & Equivalent Concept
10 mL of N/2 HCl, 20 mL of N/2 H₂SO₄ and 30 mL N/3 HNO₃are mixed together and solution made to one litre. The normality of the resulting solution is
A.N / 2
B.N/ 4
C.N✓ Correct
D.2 N
Explanation
On dilution, the resultant normality can be calculated as 1 1 2 2 2 2 1 1 2 1 2 NV N V N N N x x MOLE & EQUIVALENT CONCEPT 46 134. 1L solution of NaOH contains 4.0 g of it. What shall be the difference between molarity and the normality? (a) 0.10 (b) zero (c) 0.05 (d) 0.20 Normality = Valency factor × Molarity For NaOH, valency factor=1 ∴ For NaOH, Normality=Molarity 135. 100 ml of 0.3 N HCl is mixed with 200 ml of 0.6 N H₂SO₄. The final normality of the resulting solution will be (a) 0.1 N (b) 0.2 N (c) 0.3 N (d) 0.5 N M eq. of HCl 1 30 30 x M eq. of 2 4 0.6 200 12
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