Given, Normality of sulphuric acid ( 2 4 H SO ) 1 N = 2 N 2 N = 0.1 N The volume of sulphuric acid ( 2 4 H SO ) 1 V = 2 V =? We have, 1 1 2 2 N V N V Substituting, given values to get 3 1 1 2 2 2 0.1 2 0.1 N V V dm N x 21. Excess of carbon dioxide is passed through 50 mL of 0.5 M calcium hydroxide solution. After the completion of the reaction, the solution was evaporated to dryness. The solid calcium carbonate was completely neutralized with 0.1 N hydrochloric acid. The volume of hydrochloric acid required is (At. mass of calcium=40 (KCET 2009) (a) 200cm3 (b) 500cm3 (c) 400cm3
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