Given, Equivalent weight of metal = 9 g Vapour density of metal chloride = 59.25 g The molecular weight of metal chloride = Vapour density of metal chloride × 2 =59.25 2 118.5g x Molecular weight of metal chloride Valency = Equivalent weight of metal chloride 118.5 Equivalent weight of metal 35.5 118.5 9 35.5 2.662921348 Therefore, the atomic weight of metal = equivalent weight of metal × valency 9 2.66 23.94g x Hence, the atomic weight of metal of given metal is around 23.9 grams
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