MEDIUMMCQ SINGLEJEE Advanced ChemistryPhysical ChemistryMole _ Equivalent ConceptApplications of Strength of Solutions
A standard solution of 0.165 M HCl is being used to determine the concentration of an unknown NaOH solution. If 25.5 mL of an acid solution are required to neutralize 15.0 mL of the base, what is the molarity of the NaOH solution ?
A.(0.165)/ (25.5 + 15.0) M
B.(15.0) / (0.165) (25.5) M
C.(0.165) (15.0/25.5) M
D.(0.165) (25.5/15.0) M✓ Correct
Explanation
Given- 45 MOLE & EQUIVALENT CONCEPT 1 1 2 2 1 1 2 2 2 2 ( ) 0.165 ( ) 25.5 ml ( ) 15.0 ( ) ? M ( ) ( ) 0.165 25.5 15 0.165 25.5 15 M HCl M V HCl V NaOH ml M NaOH V HCl M V NaOH M M M >> >> x x x >> Thus, (d) is the correct option.
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