Mole fraction of ethanol =0.25 i.e. 0.25 moles of ethanol is present in 1 mole mixture ∴Moles of water present in 1 mole mixture = 0.75 ∴ wt. of ethanol =0.25 46 11.5g x ∴ wt. of water =0.75 18 13.5g x ∴wt. of solution =11.5 13.5 25g ∴% by weight= 11.5 100 46% 25 x MOLE & EQUIVALENT CONCEPT 44 The correct option is (c)
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