Consider 6 10 g of solution. Mass of 2 4 3 34.2 Al SO g Moles of 2 4 3 34.2 0.1 342 Al SO From Molecular formula, 1 mole of 2 4 3 Al SO contains 3 moles of 2 4 SO ∴ 0.1 moles of 2 4 3 Al SO will contain 0.3 moles of 2 4 SO ∴ Volume of solution 6 6 3 10 10 10 1 ml L ∴ Molarity of 3 4 4 3 0.3 3 10 10 SO x M The correct option is (a)
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