Mole fraction of 2I in 6 6 C H is 0.2 i.e. 0.2 moles 2I present in 1 mole mixture MOLE & EQUIVALENT CONCEPT 42 ∴ Moles of 6 6 C H in mixture = 0.8 ∴ Mass of 6 6 C H 3 0.8 78 62.4 62.4 10 g x x kg ∴Molality = 3 0.2 ( ) 62.4 10 Moles of solute Mass of solvent kg x 3 0.2 10 3.2 62.4 x The correct option is (b)
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