We know that in option A, Soda lime is the mixture of NaOH & CaO. In option B, Wurtz reaction, two molecules of alkyl halides combine to produce higher alkanes. Since it contains two number of carbon atoms. Therefore, methane cannot be prepared from it. 3 3 3 3 dryether/ CH – I 2Na I – CH CH – CH 2NaI → In option C, alkanes are 4 CH and 3 | 3 3 | 3 CH CH C CH CH Has sp3 carbon. In option D, Neopentane on reaction with chlorine gives neopentyl chloride as product (only one monochloro derivative). 3 3 | | 3 3 2 3 2 | | 3 3 CH CH CH —C—CH +Cl CH —
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